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8x^2+9x=1260
We move all terms to the left:
8x^2+9x-(1260)=0
a = 8; b = 9; c = -1260;
Δ = b2-4ac
Δ = 92-4·8·(-1260)
Δ = 40401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40401}=201$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-201}{2*8}=\frac{-210}{16} =-13+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+201}{2*8}=\frac{192}{16} =12 $
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